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X^2=2.4-2.4X
We move all terms to the left:
X^2-(2.4-2.4X)=0
We add all the numbers together, and all the variables
X^2-(-2.4X+2.4)=0
We get rid of parentheses
X^2+2.4X-2.4=0
a = 1; b = 2.4; c = -2.4;
Δ = b2-4ac
Δ = 2.42-4·1·(-2.4)
Δ = 15.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{15.36}}{2*1}=\frac{-2.4-\sqrt{15.36}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{15.36}}{2*1}=\frac{-2.4+\sqrt{15.36}}{2} $
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